## Newton-meters to PSI Calculator

Unit | Value |
---|

### Information:

This calculator converts torque (Nm) to pressure (PSI) using the formula:

Pressure = Torque / (2π * radius³)

Note: The conversion to PSI assumes the torque is applied to a circular area.

Based on the search results and the query, I’ll create a comprehensive table with all the essential information about converting Newton-meters (Nm) to PSI (pounds per square inch). Note that this conversion is not straightforward as it involves torque and pressure, which are different types of measurements. However, I’ll provide the necessary information to understand and perform this conversion.

Aspect | Information |
---|---|

Basic Formula | PSI = (Torque * 8.85074579) / (π * Radius²) |

Units Involved | Torque: Newton-meters (Nm) |

Pressure: Pounds per square inch (PSI) | |

Radius: Inches | |

Conversion Factor | 1 Nm = 8.85074579 in-lbf (inch-pounds force) |

π (pi) value | Approximately 3.14159 |

Key Point | The conversion depends on the radius of application |

## Important Notes:

- This conversion is not direct, as Nm is a unit of torque and PSI is a unit of pressure.
- The conversion requires knowing the radius at which the torque is applied.
- The radius must be in inches for this formula to work correctly.

## Conversion Steps:

- Convert the torque from Nm to in-lbf by multiplying by 8.85074579.
- Divide the result by (π * Radius²).
- The final result is the pressure in PSI.

## Example Conversion:

For a torque of 50 Nm applied at a radius of 2 inches:PSI = (50 * 8.85074579) / (π * 2²) ≈ 35.18 PSI

## Related Conversions:

From | To | Conversion Factor |
---|---|---|

1 Newton/square meter | 0.000145038 PSI | |

1 PSI | 6894.75729 Newton/square meter | |

1 bar | 14.5038 PSI | |

1 Pascal (Pa) | 0.000145038 PSI |

## Applications:

- Mechanical engineering
- Automotive industry (e.g., torque specifications for bolts)
- Industrial equipment design

Remember that this conversion is context-specific and should be used carefully, ensuring that you have the correct radius of application for accurate results.